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Q.

A black metal foil is warmed by radiation from a small sphere at temperature T and at a distance d it is found that the power received by the foil is P. If both the temperature and the distance are doubled, the power received by the foil will be

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a

8P

b

64P

c

16P

d

4P

answer is A.

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Detailed Solution

$I = \frac{{eσAT}^{4}}{d^{2}} \Rightarrow \frac{I_{2}}{I_{1}} = {(\frac{T_{2}}{T_{1}})}^{4} \times {(\frac{d_{1}}{d_{2}})}^{2} here I_{1} = P$

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