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A block A has a velocity of 0.6 ms^-1 to the right. Determine the velocity of cylinder B.

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1.8 m s^-1

2.4 m s^-1

3.6 m s^-1

1.2 m s^-1

answer is C.

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Detailed Solution

Tx(Hanged part) - 2Tx' (Sliding part)

$∴ x = 3 x^{'} \Rightarrow x = 3 \times 0.6 = 1.8 {ms}^{- 1}$

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