A block ‘A’ of mass 2 kg is attached to a spring of force constant K = 300 N/m as shown in the figure. Another block ‘B’ of mass 1 kg is placed on the block A. The coefficient of friction between block A and block B is 0.5, whereas that between A and ground is zero. The system of blocks starts performing S.H.M. The amplitude of S.H.M. so that ‘B’ does not slide over ‘A’ is equal to

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5 cm

10 cm

20 cm

15 cm

answer is A.

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Detailed Solution

On equating Fpseudo and Frest, we obtain

1 × f = 0.5 × 1 × g

A × ω 2 = 0.5 × 10

where

ω = K m A + m B

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