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A block A of mass 2kg rests on another block B of mass 8kg which rests on a horizontal floor. The coefficient of friction between A and B is 0.2 while that between B and floor is 0.5. When a horizontal force F of 25N is applied on the block B, the force of friction between A and B is

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3 N

4 N

2 N

Zero

answer is D.

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Detailed Solution

Maximum value of friction between B and ground

$= μ N = μ (m_{1} + m_{n}) g = (0.5) (2 + 8) (10) = 50 N$

Since, applied force $F = 25 N$ is less than 50N. Therefore, system will not move and force of friction between A and B is zero.

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