A block A of mass 4 kg is placed on another block B of mass 5 kg, and the block B rests on a smooth horizontal table. If the maximum force that can be applied on A so that both the blocks move together is 12N, the maximum force that can be applied on B for the blocks to move together will be:

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30N

15N

48N

25N

answer is D.

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Detailed Solution

When the force is applied on upper block

$F_{\max} = \frac{μ_{s} mg (M + m)}{M} = 12 N$

When the force is applied on lower block

${F^{1}}_{\max} = μ_{s} g (M + m) = \frac{12 \times M}{m} = 12 \times \frac{5}{4} = 15 N$

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