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A block A of mass 7 kg is placed on a frictionless table. A thread tied to it passes over a frictionless pulley and carries a body B of mass 3 kg at the other end. The acceleration of the system is (given g = 10 $m s^{- 2}$ )

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100 $m s^{- 2}$

3 $m s^{- 2}$

30 $m s^{- 2}$

10 $m s^{- 2}$

answer is B.

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Detailed Solution

$a = (\frac{m_{2}}{m_{1} + m_{2}}) g = (\frac{3}{7 + 3}) 10 = 3 m / s^{2}$

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