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A block A of mass 7 kg is placed on a frictionless table. A thread tied to it passes over a frictionless pulley and carries a body B of mass 3 kg at the other end. If the system is released from rest, the velocity acquired by the blocks after 2s is $(given g = 10 {ms}^{- 2})$

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$5 m s^{- 1}$

$6 {ms}^{- 1}$

$1.5 {ms}^{- 1}$

$3 {ms}^{- 1}$

answer is B.

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Detailed Solution

$a = \frac{m_{B} g}{m_{A} + m_{B}} = (\frac{30}{3 + 7}) = 3 {ms}^{- 2}$

$V = at = 6 {ms}^{- 1}$

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