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A block A of mass m is placed over a plank B of mass 2m. Plank B is placed over a smooth horizontal surface. The coefficient of friction between A and B is 0.5. Block A is given a velocity v₀towards right. Acceleration of B relative to A is

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zero

g/2

3g/4

answer is C.

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Detailed Solution

$a_{B A} = a_{A} + a_{B} = \frac{F}{m} + \frac{F}{2 m}$

= 0.5mg / m + 0.5mg/2m = (3/4)g

After A is projected over B , it will slip over B.

.: $a_{A}$ = Acceleration of A = - (µ mg) = µg

$a_{B}$ = Acceleration of B = µmg/2m = 1/2 µg

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