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Q.

A block A of mass m is placed over a plank B of mass 2m. Plank B is placed over a smooth horizontal surface. The coefficient of friction between A and B is 0.5. Block A is given a velocity v0 towards right. Acceleration of B relative to A is

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a

zero

b

g/2

c

g

d

3g/4

answer is C.

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Detailed Solution

aBA=aA+aB=Fm+F2m

= 0.5mg / m + 0.5mg/2m = (3/4)g

After A is projected over B , it will slip over B.

.: aA = Acceleration of A = - (µ mg) = µg

aB = Acceleration of B = µmg/2m = 1/2 µg

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