A block B of mass 5kg is placed on a slab A of mass 20kg which lies on a frictionless surface as shown in the figure. The coefficient of static friction between the block and the slab is 0.4 and that of kinetic friction is 0.2. If a force F = 25N acts on B, the acceleration of the slab will be

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zero

$1 m s^{- 2}$

$0.4 m s^{- 2}$

$0.5 m s^{- 2}$

answer is C.

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Detailed Solution

The maximum static friction is 20N

In this case both of the blocks will move together.

The combined acceleration will be $a = \frac{F}{m + M} = \frac{25}{5 + 20} = 1 {ms}^{- 2}$

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