A block is at rest on an inclined plane making an angle $α$ with the horizontal. As the angle $α$ of the inclination is increased, the block just starts slipping when the angle of inclination becomes $θ$ . Then the coefficient of static friction between the block and the surface of the inclined plane is

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$s i n θ$

$\tan θ$

$\cos θ$

Independent of $θ$

answer is C.

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Detailed Solution

$θ$ = Angle of repose $∴ μ = \tan θ$

angle of repose is the angle of inclination at which a body placed on it is ready to slide and the component of weight along the inclined plane is equal to limiting friction.

mg sin $α$ = $μ_{s}$ mg cos $α$

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