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Q.

A block is hanged by means of two identical wires having cross section area 1mm2 as shown. If the temperature is lowered by ΔT = 10°C, find the mass to be added to hanging mass such that the junction remains at its initial position

(α = 2×10-5/°C, Y = 5 × 1011Pa, g = 10m/s²)

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a

8 kg

b

16 kg

c

12 kg

d

4 kg

answer is C.

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Detailed Solution

Resolving tension into components T sinθ components cancel each other

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Thermal force T = YA\alpha \Delta t

2T\cos \theta = mg; 2(YA\alpha \Delta t)\cos {53^o} = m{ \times }10

2 \times 5 \times {10^{11}} \times {10^{ - 6}} \times 2 \times {10^{ - 5}} \times 10 \times \frac{3}{5} = m(10)

m = 12 kg

 

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