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A block of mass 20kg pushed by a horizontal force F on a horizontal rough plane moves with an acceleration $5 m s^{- 2}$ . When force is tripled, its acceleration becomes $18 m s^{- 2}$ . The coefficient of friction is $(g = 10 m s^{- 2}) .$

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0.8

0.67

0.25

0.45

answer is D.

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Detailed Solution

$\frac{F}{3 F} = \frac{μ m g + m (5)}{μ m g + m (18)}$

$\frac{1}{3} = \frac{μ g + 5}{μ g + 18}$

$μ g + 18 = 3 μ g + 15$

$2 μ g = 3$

$μ = \frac{3}{2 g} = \frac{3}{20} = 0.66$

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