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A block of weight 20 N is pressed against a vertical wall as shown in figure by applying a horizontal force of the block $(g = 10 m s^{- 2})$ if $μ_{k} = 0.4$ then The least horizontal force required to keep the block in equilibrium is

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40 N

20 N

50 N

10 N

answer is D.

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Detailed Solution

F = μ_{s} N

$mg = μ_{s} N$

$\frac{mg}{μ_{s}} = N \Rightarrow N= \frac{20}{0.4} = 50$

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