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A block of $0.5 kg$ is placed on a horizontal platform. The system is making vertical oscillations about a fixed point with a frequency of $0 .5 Hz$ . Find the maximum amplitude of oscillation if the block is not to lose contact with the horizontal platform

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0 .6542m

0 .852m

0 .7428m

0 .9927m

answer is B.

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Detailed Solution

ω = 2 π f = 2 \times 3.14 \times 0.5 = 3.14

$m ω^{2} A = mg$

$A = \frac{g}{ω^{2}} = \frac{9.8}{{(3.14)}^{2}}$

$A = 0.9927 m$

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