A block of ice of density $0.9gc{c}^{-1}$ and of volume 100 cc floats in water. Then volume of ice inside the water

Given that a block of ice

${\rho }_{\mathrm{ics}}=0.9\mathrm{g}/\mathrm{c}.\mathrm{c},{\mathrm{V}}_{\mathrm{ics}}=100\mathrm{c}.\mathrm{c},{\rho }_{\mathrm{w}}=1\mathrm{g}/\mathrm{c}.\mathrm{c}\text{ floats in water. }$

We know for any floating object

Weight of object = Weight of liquid displaced.

${\mathrm{m}}_{\mathrm{ice}}\mathrm{g}={\mathrm{m}}_1\mathrm{g}$

${\mathrm{V}}_{\mathrm{ice}}{\rho }_{\mathrm{ics}}={\mathrm{V}}_1{\rho }_1$

${\mathrm{V}}_1=\frac{{\mathrm{V}}_{\mathrm{ics}}{\rho }_{\mathrm{ice}}}{{\rho }_1}$

$=\frac{100\times 0.9}{1}$

${\mathrm{V}}_l=90{\mathrm{cm}}^3$