A block of ice (specific gravity $S_{i -} = 0.90$ ) is floating in a container having two immiscible liquids (one of specific gravity $S = 0.50$ and other is water) as shown in the figure. ( $H_{1}, H_{2}$ are heights of water, other liquid columns respectively.) Now the ice block melts completely, then

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$H_{2}$ will decrease

$H_{1}$ will increase

$H_{1} + H_{2}$ will remains unchanged

$H_{1} + H_{2}$ decreases

answer is A, B, D.

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Detailed Solution

Density of ice is in between that of water and liquid.Pressure at ice -liquid interface is more than the pressure at liquid -water interface .Due to this volume of water displaced by ice is less than the volume of water displaced by the ice block when it freely floats on water surface . Decrease in $H_{2} m o r e t h a n t h e i n c r e a s e i n H_{1 .}$