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Q.

A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

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a

0.67 J

b

0.34 J

c

1.00 J

d

0.16 J

answer is D.

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Detailed Solution

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Applying the law of conservation of momentum, 

1.00+0.50ν=0.50×2.00 ν=23 m/s

Initial energy Ki=12×0.5×2.002=1.00 J 

Final energy Kf=12×1.50×49=0.33 J  Loss of energy = Ki-Kf=0.67 J

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A block of mass 0.50 kg is moving with a speed of 2.00 ms-1 on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is