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Q.

A block of mass 0.5kg is moving with a speed of 2m/s on a smooth surface. It strikes another mass 1kg then they move together as a single body. The energy loss (in J) during the collision is __ .

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answer is 0.67.

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Detailed Solution

$m_{1} u_{1} + m_{2} u_{2} = (m_{1} + m_{2}) V \Rightarrow V = \frac{2}{3} m / s$

$Energy loss = \frac{1}{2} (0.5) 2^{2} - \frac{1}{2} (1.5) {(\frac{2}{3})}^{2} = 0.67 J$

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