A block of mass 1 kg is suspended by a light thread from an elevator. The elevator, starting from rest is accelerating upward with uniform acceleration 0.2 $m / s^{2}$ . The work done by tension on the block during in 1 sec is _____J.
$[g = 9.8 m / s^{2}]$

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Detailed Solution

$ω = \frac{m}{2} (g + a) a t^{2} = \frac{1}{2} (9.8 + 0.2) \times 0.2 \times 1^{2} = \frac{1}{2} \times 10 \times 0.2 \times 1^{2} = \frac{1}{2} \times 2 \times 1^{2} = 1$

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