A block of mass 1 kg lies on horizontal surface in a truck. The coefficient of static friction between the block and the surface is µ_s = 0.6. If the acceleration of the truck is 5 m/s², the friction force acting on the block is__N

Let us assume the truck has acceleration in the rightward direction. The FBD of the block in the frame of truck can be shown as From the FBD we have N=1g=10 N f_max=µN=10µ=10×0.6=6 N Applying the concept of pseudo force in the frame of truck, the force on the block is ma=1×5=5 N

Since, f_max>ma, the friction force acting over the block is f=ma=5 N