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Q.

A block of mass 10 kg is moving along x-axis under the action of force $F = 5 x N$ . The work done by the force in moving the block from $x = 2 m$ to 4m will be ____J.

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answer is 30.

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Detailed Solution

$w = \int F d x$

$w = \int_{2}^{4} 5 x d x = 5 \int_{2}^{4} x d x = 5 {[\frac{x^{2}}{2}]}_{2}^{4} = 30 J$

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