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A block of mass 10 kg is placed on a rough horizontal surface having coefficient of friction $μ = 0.5 .$ If a horizontal force of 100 N is acting on it, then acceleration of the block will be

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$15 m s^{- 2}$

$10 m s^{- 2}$

$0.5 m s^{- 2}$

$5 m s^{- 2}$

answer is C.

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Detailed Solution

$a = \frac{Applied force –Kinetic friction}{mass}$
$= \frac{100 - 0.5 \times 10 \times 10}{10} = 5 m / s^{2}$

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