Q.

A block of mass 10 kg starts sliding on a surface with an initial velocity of 9.8 ms-1. The coefficient of friction between the surface and bock is 0.5. The distance covered by the block before coming to rest is : [use g = 9.8 ms-2]

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a

4.9 m

b

19.6 m

c

12.5 m

d

9.8 m

answer is B.

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Detailed Solution

 a=μg=0.5×9.8=4.9m/s2 d=v22a=9.8×9.82(4.9) =9.8m

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