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Q.

A block of mass 10kg starts sliding on a surface with an initial velocity of 9.8ms−1.The coefficient of friction between the surface and block is 0.5. The distance covered by the block before coming to rest is 

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a

12.5 m

b

19.6 m

c

4.9 m

d

9.8 m

answer is B.

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Detailed Solution

a=−μg=−0.5×9.8=−4.9m/s2d=v22a=9.8×9.82(4.9)=9.8m

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A block of mass 10kg starts sliding on a surface with an initial velocity of 9.8ms−1.The coefficient of friction between the surface and block is 0.5. The distance covered by the block before coming to rest is