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Q.

A block of mass 15 kg is resting on a rough inclined plane as shown in figure. The block is tied by a horizontal string which has a tension of 50 N. The coefficient of friction between the surfaces of contact is:

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a

34

b

23

c

12

d

14

answer is A.

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Detailed Solution

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The string is under tension, hence there is limiting friction between the block and the plane.

 Fx = 0  μN + 50 cos 450 = 150 sin 450----(i)

 Fy  = 0  N = 50 sin 450+150 cos 450-----(ii)

Solving (i) and (ii), μ = 12

 

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