A block of mass 1kg is kept on a rough inclined plane at θ = 30º with horizontal. The block is connected with a string as shown. Between the block and inclined plane µ_s = 3 / 4 = tan37º .Then tension in the string is (g = 10ms^–2)

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< 5N but not equal to zero

> 5N

5√3N

zero

answer is D.

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Detailed Solution

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$mgsin theta = (1)(10) times frac{1}{2} = 5N$
${f_2} = mu mgcos theta = frac{3}{4} times 1 times 10 times frac{{sqrt 3 }}{2} = frac{{15sqrt 3 }}{4} = 6.495N$
$clearly;{f_2} > mgsin theta$
so body at rest and T = 0

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