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A block of mass 2 kg is on a smooth horizontal surface. A light spring of force constant 800 N/m has one end rigidly attached to a vertical wall and lying on that horizontal surface. Now the block is moved towards the wall compressing the spring over a distance of 5 cm and then suddenly released. By the time the spring regains its natural length and looses contact with the block, the velocity acquired by the block will be

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200m/s

100 m/s

2m/s

1m/s

answer is D.

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Detailed Solution

$\frac{1}{2} {Kx}^{2} = \frac{1}{2} {mv}^{2}$

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