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A block of mass 20kg is pushed with a horizontal force of 90N. If the coefficient of static & kinetic friction are 0.4 & 0.3, the frictional force acting on the block is (g=10 $m s^{- 2}$ )

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90N

80N

60N

30N

answer is C.

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Detailed Solution

m = 20kg ; F = 90N
$f_{l} = μ_{s} m g$ = 0.4 x 20 x 10 = 80N
But F > $f_{l}$
$f_{k} = μ_{k} m g$ = 0.3 x 20 x 10 = 60N

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