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A block of mass 20kg is pushed with a horizontal force of 90N. If the co-efficient of static & kinetic friction are 0.4 & 0.3, the frictional force(in N ) acting on the block is (g=10ms-2)

easy

detailed solution

Correct answer is 60

Maximum static friction = 0.4x20x10=80N. So kinetic friction will act on the block.

Kinetic friction= 0.3x20x10=60N 

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