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A block of mass $\frac{\sqrt{3}}{10}$ kg is placed on a rough horizontal surface as shown in the figure. A force of 1 N is applied at one end of the block and the block remains stationary. The normal force exerted by the surface on the block acts ( $g = 10 m / s^{2}$ )

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through the point at a distance 5 cm. from A.

through the centre of mass of the block.

through point B.

through point A.

answer is B.

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Detailed Solution

(B)
For equilibrium
$\sum \vec{F} = 0 \sum \vec{τ} = 0$
$N = \frac{\sqrt{3}}{2} - \frac{1}{2}$ ….(i)
torque about A due to all forces excluding normal force is found to be zero.

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