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A block of mass 4 kg and volume 5 x 10^-4 m³ is suspended by a spring balance in a lift which is accelerating. The apparent weight shown by the spring balance is 3 kg. Now, the block is immersed in water in a container inside the lift. The apparent weight (in kg) shown by the spring balance is

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2375

0.25

2.5

3.125

answer is B.

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Detailed Solution

$∴ F = m g - m a$

$\Rightarrow 3 g = 4 (g - a) \Rightarrow g - a = \frac{3 g}{4}$

Upthrust force $= v \times ρ (g - a) = (5 \times 10^{- 4}) (10^{3}) (\frac{3 g}{4})$

= 3.75 kg

Apparent weight $= (4 - 3.75) = 0.25 kg$

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