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A block of mass 4 kg rests on a smooth horizontal surface. A force is applied on the block which varies with displacement according to the graph shown in figure. It the block comes to rest after traversing a distance d, then find d

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3 m

4 m

2.75 m

1.5 m

answer is D.

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Detailed Solution

By work-energy theorem net work done by the applied force must be zero.

$∴ \frac{1}{2} \times 1 \times 2 + 2 \times (2 - 1) - \frac{1}{2} \times (d - 2) \times 8 = 0$

$\Rightarrow d = 2.75 m$

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