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Q.

A block of mass 4kg is hanging over a smooth and light pulley through a light and inextensible string. The other end of the string is pulled by a constant force F = 60N. The kinetic energy of the particle increases by 60J in a given interval of time. $(g = 10 m s^{- 2}) .$

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a

The tension in the string is 60N

b

Work done by the force is 180 J

c

The displacement of the block in the given interval of time is 3 metre.

d

Work done by gravity is 120 J

answer is A, B, D.

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Detailed Solution

Mass of the block =4 kg
Constant force= 60 N
Question Image
Kinetic energy =60J
Free body diagram is shown here
From work energy theorem
$W_{net} = Δ K E$
$\Rightarrow (60 - 40) S = 60$
$20 S = 60$
$S = \frac{60}{20} = 3 m$
Work done by gravity $= i . e . - 40 \times 3 = - 120 J$
Work done by tension is $60 N \times 3 = 180 J$

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