A block of mass 4kg is placed on another block B of mass 5kg and the block B rest on smooth horizontal table. If the maximum force that can be applied on A so that both the blocks move together is 12N.The maximum force that can be applied to B for the blocks to move together will be

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30N

25N

27N

48N

answer is C.

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Detailed Solution

Maximum force on A=frictional force between the surface =12N
Therefore maximum acceleration
$a_{M a x} = \frac{12}{4} = 3 m s^{- 2} ∴ F_{M a x} = 9 \times 3 = 27 N$

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