A block of mass 4kg is placed on another block B of mass 5kg and the block B rest on smooth horizontal table. If the maximum force that can be applied on A so that both the blocks move together is 12N.The maximum force that can be applied to B for the blocks to move together will be

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

30N

27N

48N

25N

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Maximum force on A=frictional force between the surface =12N
Therefore maximum acceleration
$a_{M a x} = \frac{12}{4} = 3 m s^{- 2} ∴ F_{M a x} = 9 \times 3 = 27 N$

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th