A block of mass 5 kg is at rest on a smooth horizontal surface. Water coming out of a pipe horizontally at the rate of 2 kg s^–1, hits the block with a velocity of 6ms^–1. The initial acceleration of the block is,

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$1.2 m s^{- 2}$

$2.4 m s^{- 2}$

$0.6 m s^{- 2}$

Zero

answer is C.

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Detailed Solution

The force on the block will be the given by

Force= rate of water coming out x velocity of the water.

F=2x6=12N

So, the initial acceleration will be $a = \frac{F}{m} = \frac{12}{5} = 2.4 {ms}^{- 2}$

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