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A block of mass 5 kg is (i) pushed in case (A) and (ii) pulled in case B by a force of 20 N making an angle $30^{0}$ with the horizontal, as shown in the figures. The coefficient of friction between the block and floor is $μ = 0.2$ The difference between the accelerations of the block, in case (B) and case (A) will be: $(g = 10 m / s^{- 2})$

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$0.4 m / s^{- 2}$

$3.2 m / s^{- 2}$

$0.8 m / s^{- 2}$

$0 m / s^{- 2}$

answer is C.

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Detailed Solution

$N_{1} = 60, N_{2} = 40$

$a_{1} = \frac{10 \sqrt{3} - 0.2 \times 60}{5} = 1.064 a_{2} = \frac{10 \sqrt{3} - 0.2 \times 40}{5} = 1.86$

$a_{2} - a_{1} = 0.8$

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