A block of mass 5 kg is placed on a horizontal surface with coefficient of friction $μ$ = 0.2, then the maximum and minimum value of force F for which the block remains at rest are (g = 10 $m / s^{2}$ )

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25 N ,10 N

25 N , 5 N

15 N , 10N

15 N , 10 N

answer is B.

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Detailed Solution

If it has to move right, frictional force 0.2 x 5 x 10 = 10 N acts towards left then maximum F value should be 25 N

if it has to move towards left, frictional force acts towards right. Net force 15 -10 = 5 N has to be applied towards right.

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