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A block of mass 5 kg placed on a rough inclined plane of inclination 30°. If coefficient of friction between the surfaces in contact is 0.8, the friction between the surfaces is ( g=10ms^-2)

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25 N

50 N

$20 \sqrt{3} N$

40 N

answer is A.

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Detailed Solution

$θ < α \Rightarrow f = mgsin θ$

$Where θ is the angle of inclination and α is angle of repose$

$where tanα = μ = 0.8 is more than than \tan 30^{0}$

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