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A block of mass 50 kg moved on a horizontal surface by some external force through a distance of 5m. Coefficient of friction of between the surfaces is 0.4. The work done by friction is $(g = 10 {ms}^{- 2})$

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$+ 500 J$

$- 1000 J$

$- 500 J$

$+ 1000 J$

answer is A.

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Detailed Solution

$W = \vec{f} . \vec{s} = μmgscos 180$

$= - 0.4 \times 50 \times 10 \times 5 J = - 1000 J$

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