Q.

A block of mass 5kg is suspended by means of a uniform cord of mass 2kg attached to the roof of a lift as shown. If the lift starts accelerating up witha=5mJ2(andg=10ms2) . The tension at the mid-point of the cord is

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a

90 N

b

40 N

c

100 N

d

50 N

answer is A.

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Detailed Solution

From the given data

T6g=6a

T=6(g+a)

=6[10+5]

T=90N

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