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Q.

A block of mass 6 kg is lowered with the help of a rope of negligible mass through a distance of 20 m with an acceleration of 1.96ms−2 . Work  done by the rope on the block is

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a

 235.2 J

b

−940. 8 J

c

940.8 J

d

 − 470.4 J

answer is D.

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Detailed Solution

Question Image

mg−T=ma
T=m(g−a)
=6(9.8−1.96)
T=6(7.84)
w=T.S cos180
=(47.04)(20)(−1)
=−940.8J

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