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A block of mass 6 kg is lowered with the help of a rope of negligible mass through a distance of 20 m with an acceleration of $1.96 m s^{- 2}$ . Work done by the rope on the block is

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a

235.2 J

b

$-$ 940. 8 J

c

940.8 J

d

$-$ 470.4 J

answer is D.

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Detailed Solution

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$m g - T = m a$
$T = m (g - a)$
$= 6 (9.8 - 1.96)$
$T = 6 (7.84)$
$w = T . S \cos 180$
$= (47.04) (20) (- 1)$
$= - 940.8 J$

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A block of mass 6 kg is lowered with the help of a rope of negligible mass through a distance of 20 m with an acceleration of 1.96ms−2 . Work done by the rope on the block is