A block of mass 'M' moving on the frictionless horizontal surface collides with the spring of spring constant k2 . The other end of the spring is rigidly fixed to a vertical wall. If the spring is compressed by L2. The maximum momentum of the block after collision

12K2(L2)2=p22M 12KL28=p22M⇒p2=MKL28 p=L2MK2

A block of mass 'M' moving on the frictionless horizontal surface collides with the spring of spring constant k2 . The other end of the spring is rigidly fixed to a vertical wall. If the spring is compressed by L2. The maximum momentum of the block after collision

12K2(L2)2=p22M 12KL28=p22M⇒p2=MKL28 p=L2MK2

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A block of mass $' M'$ moving on the frictionless horizontal surface collides with the spring of spring constant $\frac{k}{2}$ . The other end of the spring is rigidly fixed to a vertical wall. If the spring is compressed by $\frac{L}{2} .$ The maximum momentum of the block after collision

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$\sqrt{M K} L$

$\frac{K L^{2}}{2 M}$

$\frac{L}{2} \sqrt{\frac{M K}{2}}$

$\frac{M L^{2}}{K}$

answer is C.

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$\frac{1}{2} \frac{K}{2} {(\frac{L}{2})}^{2} = \frac{p^{2}}{2 M}$

$\frac{1}{2} \frac{K L^{2}}{8} = \frac{p^{2}}{2 M} \Rightarrow p^{2} = \frac{M K L^{2}}{8}$

$p = \frac{L}{2} \sqrt{\frac{M K}{2}}$

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A block of mass 'M' moving on the frictionless horizontal surface collides with the spring of spring constant k2 . The other end of the spring is rigidly fixed to a vertical wall. If the spring is compressed by L2. The maximum momentum of the block after collision

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A block of mass $' M'$ moving on the frictionless horizontal surface collides with the spring of spring constant $\frac{k}{2}$ . The other end of the spring is rigidly fixed to a vertical wall. If the spring is compressed by $\frac{L}{2} .$ The maximum momentum of the block after collision