A block of mass m = 2kg pulled by a force F = 40 N upwards through a height h = 2m. The work done on the block by the applied force F and its weight mg are (g=10 ms−2)

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A block of mass m = 2kg pulled by a force F = 40 N upwards through a height h = 2m. The work done on the block by the applied force F and its weight mg are $(g = 10 {ms}^{- 2})$

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- 80 J, - 40 J

$80 J, - 40 J$

- 40 J, - 40 J

- 80 J, - 80 J

answer is C.

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Detailed Solution

(i) given that

m = 2 k g

F = 40 N

h = 2 m

Work done by the applied force.

W = F. S

$W = 40 \times 2$

W = 80J

(ii) now work done by it’s weight

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W = mgh (mg is acting in downward direction)

= –2×10×2

= – 40J

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