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A block of mass M is connected to a spring of force constant k and is placed on a smooth horizontal surface. The block is displaced and compressed the spring by “A”. The lock is left free to move from this position, when the block is at a distance A/2 from mean position it collides elastically with the identical block. Time to be taken by block to move from extreme position to mean position is....

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$\frac{π}{2} \sqrt{\frac{2 M}{K}}$

$\frac{π}{2} \sqrt{\frac{M}{K}}$

$\frac{5 π}{6} \sqrt{\frac{M}{K}}$

$2 π \sqrt{\frac{M}{K}}$

answer is D.

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Detailed Solution

$\begin{array}{l} P Q = Q O; t_{P O} = t_{P Q} + t_{Q O} \\ t_{P Q} = \frac{T}{6} + t_{Q o} \dots . . (1); T = 2 π \sqrt{\frac{M}{K}} . \end{array}$

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