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A block of mass M is kept on a platform which is accelerated upward with a constant acceleration 'a' during the time interval T. The work done by normal reaction between the block and platform is

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$- \frac{{MgaT}^{2}}{2}$

$\frac{1}{2} {Ma}^{2} T$

Zero

$\frac{1}{2} M (g + a) a T^{2}$

answer is B.

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Detailed Solution

Work done by normal reaction

$= Nh = M (g + a) \frac{1}{2} {aT}^{2} = \frac{1}{2} M (g + a) {aT}^{2}$

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