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A block of mass m is lying on a another block of mass M, lying on a horizontal frictionless surface as shown in Figure. If the coefficient static friction between the two blocks is $μ_{s}$ , the minimum horizontal force F that must be applied to block of mass m so that it moves over block of mass M is

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zero

$mg / μ_{s}$

$μ_{s} mg$ (1+ $\frac{m}{M})$

answer is D.

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Detailed Solution

When block m is on the verge of moving on block M , acceleration of the upper block

$a_{u} = \frac{F - μ m g}{m} . A t t h a t i n s \tan t a c c e l e r a t i o n o f t h e l o w e r b l o c k, a_{L} = \frac{μ m g}{M} . B u t a_{u} = a_{L} . S o l v i n g, F = μ m g (1 + \frac{m}{M})$

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