Q.

A block of mass m is lying on a horizontal surface. The coefficient of friction between block and the surface is μ . The minimum possible force needed to move the block on the surface is

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a

μmg

b

mgμ

c

mgμ1+μ2

d

mgμ2+1μ

answer is C.

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Detailed Solution

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N=mgFsinθ

Fcosθ=f=μN

Fcosθ=μmgμFsinθ

F(cosθ+μsinθ)=μmg

F=μmg/(cosθ+μsinθ)

μ=tanϕ       ϕangleoffriction

F=mgsinϕ/cosϕcosθ+sinϕsinθcosϕ

F=mgsinϕcosθcosϕ+sinθsinϕ

F=mgsinϕcos(θϕ)

F to be minimum if cos(θϕ)=1θϕ=0

θ=ϕ

tanϕ=tanθ=μ

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Fmin=mgsinθ

Fmin=μmg1+μ2

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