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A block of mass m is placed at rest on an inclined plane of inclination $θ$ to the horizontal. If the coefficient of friction between the block and the plane is $μ$ , then the total force, the inclined plane exerts on the block is

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$μ m g \cos θ$

$m g \sin θ$

$μ m g \tan θ$

answer is A.

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Detailed Solution

Only two forces are acting, mg and net contact force (resultant of friction and normal reaction) from the inclined plane. Since, the body is at rest. Therefore, these two forces should be equal and opposite. $∴$ Net contact force = mg

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