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Q.

A block of mass m is placed on a smooth wedge of inclination θ . The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be

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a

mg/cosθ

b

mg

c

mgcosθ

d

mgsinθ

answer is A.

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Detailed Solution

N=masinθ+mgcosθ 

Question Image

 

Also mgsinθ=macosθ

From (2) a=gtanθ

∴N=mgsin2θcosθ+mgcosθ ,

or  N=mgcosθ

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