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Q.

A block of mass m is placed on a surface with a vertical cross section given by y = x³/6. If the coefficient of friction is 0.5, the maximum height above the ground at which the block can be placed without slipping is

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a

$\frac{1}{2} m$

b

$\frac{1}{6} m$

c

$\frac{2}{3} m$

d

$\frac{1}{3} m$

answer is B.

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Detailed Solution

At the instant of just sliding μ = tanθ
$0.5 = \frac{d y}{d x} = \frac{x^{2}}{2} \Rightarrow x = \pm 1$

H=’y’ at x=1= $\frac{1}{6} m$

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